Skip Nav Destination
Coordination Chemistry Fundamentals
Organometallic Chemistry
Edited by
Hiroshi Nakazawa;
Hiroshi Nakazawa
Osaka Metropolitan University, Japan
Search for other works by this author on:
Julian Koe
Julian Koe
International Christian University, Japan
Search for other works by this author on:
Hardback ISBN:
978-1-83916-406-4
PDF ISBN:
978-1-83916-420-0
EPUB ISBN:
978-1-83916-421-7
Special Collection:
2021 ebook collection
No. of Pages:
284
Publication date:
09 Jul 2021
Book Chapter
Chapter 13: Problem Solutions
By
Hiroshi Nakazawa
Osaka City University Japan nakazawa@sci.osaka-cu.ac.jp
Hiroshi Nakazawa
Search for other works by this author on:
-
Published:09 Jul 2021
-
Special Collection: 2021 ebook collection
Citation
Hiroshi Nakazawa, 2021. "Problem Solutions", Organometallic Chemistry, Hiroshi Nakazawa, Julian Koe
Download citation file:
Answers to Problem 1 (See Section 2.4.4)
| 1) [Cr(CO)6] | 6(Cr) + 2(CO) × 6 = 18 |
| 2) [CpFe(CO)2Me] | 5(Cp) + 8(Fe) + 2(CO) × 2 + 1(Me) = 18 |
| 3) [Mo(C6H6)2] | 6(Mo) + 6(C6H6) × 2 = 18 |
| 4) [(CO)5Mn-Mn(CO)5] | 2(CO) × 5 + 7(Mn) + 1(Mn(CO)5) = 18 |
| 5) [Fe(CO)3(PPh3)2] | 8(Fe) + 2(CO)) × 3 + 2(PPh3) × 2 = 18 |
| 6) [Fe(H)2(CO)4] | 8(Fe) + 1(H) × 2 + 2(CO) × 4 = 18 |
| 7) [Co(CN)2(CO)(PEt3)2]− | 9(Co) + 1(CN) × 2 + 2(CO) + 2(PEt3) × 2 + 1 (minus charge) = 18 |
| 8) [Pt(C2H4)Cl3]− | 10(Pt) + 2(C2H4) + 1(Cl) × 3 + 1(minus charge) = 16 |
| 9) [CpFe(CO)2(PMe3)]+ | 5(Cp) + 8(Fe) + 2(CO) × 2 + 2(PMe3) – 1(plus charge) = 18 |
| 10) [(η5-C5H5)(η1-C5H5)Ru(CO)2] | 5(η5-C5H5) + 1(η1-C5H5) +8(Ru) + 2(CO) × 2 = 18 |
| 11) [Ni(Ph)2(PPh3)2] | 10(Ni) + 1(Ph) × 2 + 2(PPh3) × 2 = 16 |
| 12) [CpOs(η3-C3H5)(CO)] | 5(Cp) + 8(Os) + 3(η3-C3H5) + 2(CO) = 18 |
| 13) [Cp2Mo(C2H2)] | 5(Cp) × 2 + 6(Mo) + 2(C2H2) = 18 |
| (In this case, the 18-electron rule takes precedence and C2H2 acts as a 2e donor ligand.) | |
| 14) [Pd(PEt3)2(OMe)2] | 10(Pd) + 2(PEt3) × 2 + 1(OMe) × 2 = 16 |
| 15) [(η3-C3H5)Pd(μ-Cl)2Pd(η3-C3H5)] | 3(η3-C3H5) + 10(Pd) + 1(one of (μ-Cl)2) + 2(the other μ-Cl) = 16 |
| 16) [Mn(CO)5{C(O)Me}] | 7(Mn) + 2(CO) × 5 + 1(C(O)Me) = 18 |
| 1) [Cr(CO)6] | 6(Cr) + 2(CO) × 6 = 18 |
| 2) [CpFe(CO)2Me] | 5(Cp) + 8(Fe) + 2(CO) × 2 + 1(Me) = 18 |
| 3) [Mo(C6H6)2] | 6(Mo) + 6(C6H6) × 2 = 18 |
| 4) [(CO)5Mn-Mn(CO)5] | 2(CO) × 5 + 7(Mn) + 1(Mn(CO)5) = 18 |
| 5) [Fe(CO)3(PPh3)2] | 8(Fe) + 2(CO)) × 3 + 2(PPh3) × 2 = 18 |
| 6) [Fe(H)2(CO)4] | 8(Fe) + 1(H) × 2 + 2(CO) × 4 = 18 |
| 7) [Co(CN)2(CO)(PEt3)2]− | 9(Co) + 1(CN) × 2 + 2(CO) + 2(PEt3) × 2 + 1 (minus charge) = 18 |
| 8) [Pt(C2H4)Cl3]− | 10(Pt) + 2(C2H4) + 1(Cl) × 3 + 1(minus charge) = 16 |
| 9) [CpFe(CO)2(PMe3)]+ | 5(Cp) + 8(Fe) + 2(CO) × 2 + 2(PMe3) – 1(plus charge) = 18 |
| 10) [(η5-C5H5)(η1-C5H5)Ru(CO)2] | 5(η5-C5H5) + 1(η1-C5H5) +8(Ru) + 2(CO) × 2 = 18 |
| 11) [Ni(Ph)2(PPh3)2] | 10(Ni) + 1(Ph) × 2 + 2(PPh3) × 2 = 16 |
| 12) [CpOs(η3-C3H5)(CO)] | 5(Cp) + 8(Os) + 3(η3-C3H5) + 2(CO) = 18 |
| 13) [Cp2Mo(C2H2)] | 5(Cp) × 2 + 6(Mo) + 2(C2H2) = 18 |
| (In this case, the 18-electron rule takes precedence and C2H2 acts as a 2e donor ligand.) | |
| 14) [Pd(PEt3)2(OMe)2] | 10(Pd) + 2(PEt3) × 2 + 1(OMe) × 2 = 16 |
| 15) [(η3-C3H5)Pd(μ-Cl)2Pd(η3-C3H5)] | 3(η3-C3H5) + 10(Pd) + 1(one of (μ-Cl)2) + 2(the other μ-Cl) = 16 |
| 16) [Mn(CO)5{C(O)Me}] | 7(Mn) + 2(CO) × 5 + 1(C(O)Me) = 18 |
You do not currently have access to this chapter, but see below options to check access via your institution or sign in to purchase.
Digital access
$64.60
